|
|
|
|
|
by sixfiveotwo
590 days ago
|
|
My intuition when reading the first lines of this article was that, just like when searching exhaustively for the correct combination on a padlock, one would cycle through each subgroup, where each of them would represent a digit on the lock. On the lock, one would do 9 steps (not 10, as this would loop the lock to a previously seen combination) on the least significant digit, then propagate the carry to the next digits. But it seems that this more complicated than that, as the steps at which subgroups connect (the carry) are not always the same? |
|