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by quantadev
596 days ago
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> not useful for the task of finding an optimal candidate That statement is just flat out incorrect on it's face, however it did make me think of something I hadn't though of before, which is this: Embedding vectors can be made to have a "scale" (multiplier) on specific terms which represent the amount of "weight" to add to that term. For example if I have 10 years experience in Java Web Development, then we can take the actual components of that vector
embedding (i.e. for string "Java Web Development") and multiply them by some proportionality of 10, and that results in a vector that is "Further" into that direction. This represents an "amount" of directional into the Java Web direction. So this means even with vector embeddings we can scale out to specific amounts of experience. Now here's the cool part. You can then take all THOSE scaled vectors (one for each individual job candidate skill) and average them to get a single point in space which CAN be compared as a single scalar distance from what the Job Requirements specify. |
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