[coffeeaddict1]

> I just looked up ZX calculus, and I am sure you can formulate that better by not mentioning CT at all.

Based on what? Sorry, but what you're saying is beyond arrogant (considering you have zero knowledge of the subject).

[auggierose]

As usual, quick googling reveals that the ZX calculus is really just a CT repackaging of Penrose diagrams, which were discovered and used without any involvement of CT.