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by bfrog
607 days ago
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This is generics. Calling x.some_func() in rust means there is either a type specific function or an impl trait. If more than one option is there rust requires more explicitly calling the types function with x as a parameter. E.g. Something::some_func(x) I’ve never read rust code where I’m entirely guessing which overloaded function is being called. C++ has an entire set of overload resolution rules around this! https://en.cppreference.com/w/cpp/language/overload_resoluti... |
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Having learned Go and Rust in the last two years, it occurs to me that -- if this can be made into a trivia, and considering all the things in C++ like friend class, nested class, public/protected/private inheritance matrix and all the "possibilities" out there, it seems this language is seriously f*cked up.