[RGamma]

It's easy enough to prove that you can do it without revealing the method. E.g. try factoring

828779882149581516608371895000952095542845654164714667404503828622425254433342333212851597308609571788866517548728051290486514664536526513189610109365786163329028919611934048763953195663095107461374317207248372551320318065286778764851524374520963310255832610228096092786871242729401067756589198807809654636897168275783949053564041346551042535096866922015555150328851789814755353416970423293384462938529229504776847343483500413283766835786156833770930672918554267754213460743282944441316468046663307327275988621784143792477230074308093417024020208503042995610623838662249568686237622629268718158351345829871048206694289429425274539851662996156137399085654359584771983891913824833817853560160370503998066766467250804875540795977735547426031658244875845477862785702453425686697408010169925029349599361158016358703937995386113446794769936324484430612916057117051719218218325916643485253731482150206366098004386513239730239094402800085867574268581700189625680138287068263081046491346243525955935799560535151953302697995913599546972232450859613369273247939285956354820615032954994533035265826732005181461819339324028400499227345113535895172348378848646216279768426623149666406923929418315334152487496960069280408337431573225747461462095889

which I created by multiplying two primes generated by openssl prime -generate -bits 2048

[zekchelovek]

If you are a qualified buyer, and want to pay at least $24000, you can take one of the methods and check it yourself (there are more than one, but work on same principle). I don't put the algorithms in computers, so any checking above a 9 digit product will have to be done by someone else. There is enough of a clue in the ebay description to figure it out yourself, maybe. It seems obvious to me since i already know the answer. I assume now that capable mathematicians can make the connections much faster than i did. Let me know if you figure it out and factor your test number quickly. Then again, i really don't care if you do, which I'd bet all my money and yours too that you won't figure it out.

[gryfft]

https://en.m.wikipedia.org/wiki/Pig_in_a_poke

[RGamma]

Hehe, thanks, I'll pass. But good luck.

[mikewarot]

I've got to admit, I've been NerdSniped by this one. I've been putzing around in Python for hours now.

Factoring large numbers always sucks me in.

[zekchelovek]

Play with it, and you may just figure it out. I'm glad someone gets something interesting out of my posts.