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by magicalhippo
637 days ago
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Sorry, was on mobile so hadn't patience to type examples. SELECT
column1,
(
SELECT column2
FROM table_b
WHERE table_a.id = table_b.a_id
) as b_column2,
(
SELECT column3
FROM table_b
WHERE table_a.id = table_b.a_id
) as b_column3
FROM table_a
It might look like a lot more work, but in my experience it's usually a lot faster. YMMV but check it. |
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If table_b has an index on id,column2,column3 (or on id INLUDEing column2,column3) I would expect the equivalent JOIN to usually be faster. If you have a clustered index on Id (which is the case more often than not in MS SQL Server and MySQL/InnoDB) then that would count for this unless the table is much wider than those three columns (so the index with its selective data would get many rows per page more than the base data).
Worst (and fairly common) case with sub-selects like that is the query planner deciding to run each subquery one per row from table_a. This is not an issue if you are only returning a few rows, or just one, from table_a, but in more complex examples (perhaps if this fragment is a CTE or view that is joined in a non-sargable manner so filtering predicates can't push down) you might find a lot more rows are processed this way even if few are eventually returned due to other filters.
There are times when the method is definitely faster but be very careful with it (test with realistic data sizes and patterns) because often when it isn't, it really isn't.