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by ryandv 647 days ago
Consider async-await a syntactic sugar over Promises (from JavaScript). Then, Promises constitute an instance of the Monad typeclass where monadic `bind` or (>>=) is `Promise.then()`, and `return` is `Promise::resolve()`.

Here is a translation of a modification of the example given in [1]:

    const promise1 = Promise.resolve(123);

    promise1.then(v => v * 2).then((value) => {
      console.log(value);
      // Expected output: 246
    });
into Haskell:

    ghci> let promise1 :: IO Int = return 123
    ghci> promise1 >>= (return . (* 2)) >>= print
    246
One key discrepancy worth pointing out is that in the `Promise.then()` API of JavaScript, the function provided to `then` (e.g. `v => v * 2` above) is implicitly composed with a call to `::resolve` in order to turn that function's pure return value, the `Number` 246, into a Promise resolving into the `Number` 246; in Haskell, this operation must be made explicit (hence the composed function `return . (* 2)` passed to the first application of (>>=) or `bind`).

You could say that the instance method `Promise.then()` expects an argument of type (a -> b), with the return value of type `b` being implicitly and automatically wrapped into a Monad `m b`, whereas Haskell's bind expects an argument of type (a -> m b) on that operator's right-hand side, with the return value explicitly wrapped into a Monad `m b` by the provided function argument itself.

[0] https://wiki.haskell.org/Monad

[1] https://developer.mozilla.org/en-US/docs/Web/JavaScript/Refe...

1 comments

Maybe I’m confused, but I dont see how Promise.then() corresponds to bind? If I understand correctly, the point of the bind function is you pass a callback which itself return the monad type. But the Promise.then() callback should not return a monad but just the regular result value of invoking the callback.

So in essence Promise.then() is like Array.map() while bind is like Array.flatMap()

Edit: It seems you are correct, you can indeed return a promise in the callback and it compose correctly. But in your example the callback does not return a promise and is therefore not an example of monadic bind.

I had a caveat in my original post re. the implicit wrapping of the `Promise.then()` callback's (pure) return value in a new Promise, and how this differs from Haskell's monadic bind; I had hoped to make a loose analogy while pointing out the differences for the sake of illustration. However it is indeed also possible to return a Promise from `.then()`'s callback, which is closer to Haskell's bind: [0]

    The behavior of the returned promise (call it p) depends on the handler's
    execution result, following a specific set of rules. If the handler function:

    * returns a value: p gets fulfilled with the returned value as its value.

    [...]

    * returns an already fulfilled promise: p gets fulfilled with that promise's value as its value.
... then you can obtain a solution closer to the Haskell translation by using the behaviour of the second cited bullet point from the MDN article:

    const promise1 = Promise.resolve(123);

    promise1.then(v => Promise.resolve(v * 2)).then((value) => {
      console.log(value);
      // Expected output: 246
    });
[0] https://developer.mozilla.org/en-US/docs/Web/JavaScript/Refe...
This article argues that while promises support the required operations for monad, they do not support the monad laws:

https://www.siawyoung.com/promises-are-almost-monads/

It's a good point. `Promise::resolve()` "flattens nested layers of promise-like objects (e.g. a promise that fulfills to a promise that fulfills to something) into a single layer." [0]

The example was meant to be more of an illustrative analogy than an exact correspondence.

[0] https://developer.mozilla.org/en-US/docs/Web/JavaScript/Refe...