[tom_]

new[] and delete[] both know the type of the object. Therefore both know whether a destructor needs to be called.

When a destructor doesn't - e.g., new int[] - operator new[] is called upon to allocate N*sizeof(T) bytes. The code stores off no metadata. The result of operator new[] is the array address.

When a destructor does - e.g., new std::string[] - operator new[] is called upon to allocate sizeof(size_t)+N*sizeof(T) bytes. The code stores off the item count in the size_t, adds sizeof(size_t) to the value returned by operator new[], uses that as the address for the array, and calls T() on each item. And delete[] performs the opposite: fishes out the size_t, calls ~T() on each item, subtracts sizeof(size_t) from the array address, and passes that to operator delete[] to free the buffer.

(There are also some additional things to cater for: null checks, alignment, and so on. Just details.)

Note that operator new[] is not given any information about whether a destructor needs to run, or whether there is any metadata being stored off. It just gets called with a byte count. Exercise caution when using placement operator new[], because a preallocated buffer of N*sizeof(T) may not be large enough.