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by sakras
680 days ago
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Unfortunately not :) On a given implementation of C, a pointer has some specific size (let's call it S). This means that we can address 2^S bytes of memory. Each byte has CHAR_BIT bits, so can be in 2^CHAR_BIT states, meaning we have 2^(S + CHAR_BIT) possible states memory can be in. Since there's a finite number of states, it's not a Turing machine. |
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