[lispm]

Technically this works in Scheme, but not in Lisp.

In Common Lisp one would need to write

    (funcall (if (< 1 0) (function +) (function *)) 42 100)

[behnamoh]

You're right, the example I wrote was in Racket. I didn't know "everything is an expression" wouldn't work in CL.

[kagevf]

Everything is still an expression in CL, but you have to account for different namespaces.

Also, the above can be further shortened to:

  (funcall (if (< 1 0) #'+ #'*) 42 100)