Hacker News new | ask | show | jobs
by Terr_ 703 days ago
> If I recall correctly [...] as much energy released as an atomic bomb.

That can't be true, but perhaps you saw something about temperatures which resembled those from a nuclear-bomb instead? (The key being that much much less mass is getting heated, and stays that way for a much shorter time.)

____________

One quick set of reasoning is this: Energy cannot be created or destroyed, and there's no reason to think the popping-bubble is causing seawater to undergo nuclear fusion, so the limit is whatever it takes for someone to repeatably set up the situation. (So basically the energy to dropping ballast-and-bubble to the bottom of the sea, popping the bubble, and then pulling the ballast back up.) Tedious, but hardly nuclear-bomb territory.

A second approach is to imagine the collapse as a giant column of water falling like weight into the gap. Imagine a magic-glass box 1x1x1 meter holding a vacuum, sunk 10km below the surface. That's 10,000 m^3 of water and roughly ~10,000kg of mass poised to fall 1m. Gravitational potential energy: ~98 kilojoules.

For comparison, that's the energy of ~3 liters of gasoline, although getting it to explode in a similarly-simultaneous way would be tricky. (Power = Energy / Time.) In contrast, the Hiroshima explosion was ~63 terajoules.

1 comments

Your conclusion of ~3L of gasoline is right, but it looks like you dropped a few zeroes on the way there - your example of 1x1x1m sunk 10km below the surface would be sitting beneath 10,000,000kg of mass, not 10,000kg.

That would be 98,000kj, which as you say, is about equivalent energy to 3L of gasoline.

And for reference: a ultra-tiny tactical nuclear bomb would still be >1 GJ.