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by moonchild
706 days ago
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> 1/t^p i don't think that's right. it's just 1/t. after all, after t time, one task must have made progress; since there are t tasks, the probability that i'm the task that made progress is just 1/t the primary point of confusion, i think, is that getting interrupted does not mean that you are necessarily going to lose the cas |
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