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by gpderetta
718 days ago
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> [...] The printed result would be 0. This is because we value-initialize t and, since T has a non-user-provided default constructor, the object is zero-initialized (hence t.x is zero-initialized) then default-initialized (calling the implicitly-defined default constructor, which does nothing). T̶h̶a̶t̶ d̶o̶e̶s̶n̶'t̶ s̶e̶e̶m̶ c̶o̶r̶r̶e̶c̶t̶:̶ a̶ d̶e̶f̶a̶u̶l̶t̶e̶d̶ c̶o̶n̶s̶t̶r̶u̶c̶t̶o̶r̶ s̶t̶i̶l̶l̶ d̶e̶f̶a̶u̶l̶t̶-̶i̶n̶i̶t̶i̶a̶l̶i̶z̶e̶s̶ t̶h̶e̶ m̶e̶m̶b̶e̶r̶s̶, n̶o̶t̶ v̶a̶l̶u̶e̶ i̶n̶i̶t̶i̶a̶l̶i̶z̶e̶. I̶ d̶o̶n̶'t̶ t̶h̶i̶n̶k̶ t̶h̶e̶r̶e̶ i̶s̶ a̶n̶y̶ d̶i̶f̶f̶e̶r̶e̶n̶c̶e̶ b̶e̶t̶w̶e̶e̶n̶ d̶e̶f̶a̶u̶l̶t̶i̶n̶g̶ i̶n̶l̶i̶n̶e̶ a̶n̶d̶ o̶u̶t̶ o̶f̶ l̶i̶n̶e̶. G̶C̶C̶ s̶e̶e̶m̶s̶ t̶o̶ a̶g̶r̶e̶e̶:̶ h̶t̶t̶p̶s̶:̶//g̶c̶c̶.g̶o̶d̶b̶o̶l̶t̶.o̶r̶g̶/z̶/r̶4̶r̶e̶5̶T̶E̶5̶a̶ edit: I missed that the author is actually value-initializing x!!! The result definitely violates expectations! Generally, the details of the rules are arcane and sometimes have non-sensical dark corners having been extended and patched up for the last 40 years. But 99.9%[1] of the time you get what you expect. I big improvement would be making default initialization explicit, and otherwise always value initialize. Explicit value initialization is so common that the very rare times I want default initialization (to avoid expensively zeroing large arrays) I need to write a fat comment. Writing "std::array<int, 100> = void;" (or whatever the syntax would be) would be much better. [1] I had an extra 9 here... I hedged. |
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