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by ajkjk 716 days ago
The difference is that I'm interested in a version of physics and economics that is not aware of the distinction between 'real' and 'rational'. Hence none of that should make a difference.
2 comments

If you work with mostly continous and/or well behaved functions you do not need most of these.

I suspect that in both physics and economics you might end up using stochastic methods that use concepts and techniques similar to those of measure theory

then you are interested in a version of physics that doesn't exist, even though some might choose to supress the details at low level
Er? No I'm describing actual physics. Physics does not care about rational vs reals. Nothing is measured to infinite accuracy anyway.
One thing that is used a lot in physics are known as Dirac Deltas[0] that is, in very informal terms, the derivative of the function f(x) = 0 for negative x otherwise f(x) = 1.

Physics are very good at working with concepts and abstraction before any formal mathy justifications can be found, but the only way to formaly work with a dirac delta that makes sense formally is defining it in terms of measures

[0] https://en.wikipedia.org/wiki/Dirac_delta_function

That is not true, it is not the 'only way' to formally deal with them. A better way to think of them is as the vector space dual of functions (/forms) under the pairing given by integration. No measures required. The measure theoretic explanation is very much "fitting delta functions into our existing machinery" rather than any sort of inherent requirement.

Actually an even better way to think of delta functions is just as a geometric object, a point (or line/plane/etc). Which is somewhat related to the measure theoretic version, but much more simple to think about.

You need measures to define the vector spaces that those (what you call "forms", and others call "distributions") act on...

Not that it would be impossible to define everything without measures (or even without real numbers), but it's really not clear how to go about it.

Even if accuracy is finite, the fact that, for example, circles aren't polygons is definitely relevant to physics. You might be able to get all of the relevant physics you need without the continuum by working with several disjoint sets of numbers (the rationals, the rationals-multiplied-by-pi, the rationals-multiplied-by-e, etc) but I'm not even sure of that.
If you look close enough, from the physics point of view, all circles are polygons, and, also, they aren’t really flat.

Zeroes and infinities are problematic in physics. Physics and math aren’t the same discipline, and it’s dangerous to conflate them.

I’m pretty sure there will be a point where you’ll have a light-emitting superconductor on your way to an infinite current.