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by Maxatar
711 days ago
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Exactly, so then we agree, there is nothing useful about an algorithm that can decide whether one specific Turing machine halts. Utility only emerges from an algorithm that can decide whether entire classes of other Turing machines halt, not from whether a particular machine does. |
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Yes there is. If someone gives me a working algorithm (this means one algorithm, not two algorithms either of which may work or not as you've been doing) which can provably decide whether the machine encoding the Goldbach conjecture halts or not, that is a very useful algorithm.
I must insist that giving two algorithms and saying "one of them works" without telling me which one works is is not a valid answer, since that is strictly different from giving a working algorithm which I can run in finite time in order to find out one correct answer.
You said this yourself earlier:
> The Turing machine that encodes the Goldbach conjecture proves the conjecture if it halts, and disproves the conjecture if it doesn't halt. That is an interesting and meaningful property of such a Turing machine.