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by mturmon
729 days ago
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Definitely. Taking this to its logical end leads to a beautiful concise notation that I learned from David Pollard: - You literally identify sets with their indicators: they are the same. - You identify the “P” operator as expectation (integration) with respect to the underlying measure, and next… - You note that integration is linear, so you use linear operator notation everywhere you’d use P. So if “A” is a set, you just write P A = 0.5 This is equivalent to: P A = P 1[ω ∈ A] = ∫ 1[ω ∈ A] dP(ω) in Lebesgue notation. There’s an example on page 2 of http://www.stat.yale.edu/~pollard/Courses/241.fall2014/notes... although he’s not using measure theory there. It can be really clean and terse especially when doing bounds for random variables. |
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