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by nbadg
728 days ago
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Yes. The usual way to do this is to bind them as defaults to an argument, for example: def loop():
for number in range(10):
def func_w_closure(_num=number):
return _num
yield func_w_closure
This works because default arguments in python are evaluated exactly once, at function definition time. So it's a way of effectively copying the ``number`` out of the closure[1] and into the function definition.[1] side note, closures in python are always late-binding, which is what causes the behavior in OP |
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For those who prefer a functional style, functools.partial can also solve this problem.
(I use Python, and I like a lot of things about Python, but I don’t like its scoping rules at all, nor do I like the way that Python’s closures work. I would use a double lambda.)