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by ldunn 741 days ago
Strain drops off as 1/r, not 1/r^2
1 comments
rachofsunshine 741 days ago
Oh. Well, silly me. I did double check that it's inverse-square, but apparently not deeply enough - the energy is, but the amplitude isn't. Which makes sense if I think about it a little more (it's basically a spring, so energy ~ displacement^2)

For other readers, this poster's correction is right, here's an astronomy SA thread on it. https://astronomy.stackexchange.com/questions/34761/why-does...

I swear, the one time I try posting outside my areas of expertise :D

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