[pdonis]

> the latitudenal geodesic

There is no such thing. A curve of constant latitude on Earth, except for the equator, is not a geodesic.

> You cannot claim that one geodesic is more “straight” than another in 3d Euclidean geometry

In terms of 3D Euclidean geometry, neither a curve of constant latitude on Earth's surface nor a great circle on Earth's surface is a straight line/geodesic. Both are curved.

If you restrict to the 2D surface of the Earth, a great circle is a geodesic but a curve of constant latitude, except for the equator, is not.

[tacitusarc]

You're right, so if the puzzle restricts one (arbitrarily) to geodesics as the only valid straight-lined curve (?), it becomes nonsense because the only easterly geodesic is at the equator, and seattle is not at the equator.

[pdonis]

> the only easterly geodesic

Wrong. There is a perfectly good great circle passing through Seattle and pointing due east at the point where it passes through Seattle. The author showed it to you in the article. That geodesic does not always point due east, but nothing in the article said it had to. The article only said you have to face due east at the start, not that you need to continue facing that way.

[lxgr]

Except that the original instruction was "straight line", not "geodesic", so does it matter all that much which kind of non-straight-line one follows?

[pdonis]

> the original instruction was "straight line", not "geodesic"

If you're working within a 2-sphere, such as the Earth's surface, or indeed any non-Euclidean geometry, they mean the same thing. More precisely, there are no "straight lines" in the exact sense you mean in a non-Euclidean geometry, but there are geodesics that satisfy all of the geometric properties of "straight lines" within that non-Euclidean geometry.

[lxgr]

Nowhere did TFA define that we're working within a 2-sphere, though!

[pdonis]

Yes, it did:

"Then start traveling forward, in a straight line along the Earth’s surface."