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by hi-v-rocknroll
741 days ago
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Formats, plural. sign:explicit leading mantissa bit:mantissa bits:exponent bits 1:0:(P-1):(8-P) where P ∈ [1,7] P ∈ [3,5] appears to be more useful binary8p3 -> 1:0:2:5 binary8p4 -> 1:0:3:4 binary8p5 -> 1:0:4:3 Edge cases: P = 8 would disallow all exponent bits, leaving a sign bit and 7 explicit mantissa bits of precision P = 0 would be unsigned and 8 exponent bits with only an implicit precision bit but no explicit mantissa bits |
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- There is only one Zero (encoded as 0x00), no negative-zero
- There is only one NaN (encoded as 0x80)