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by EVa5I7bHFq9mnYK
750 days ago
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If the percentage of noisy apartments were 90%, the probability of me randomly landing in 6 quiet apartments out of 6 would be 0.1^6, or one in a million. If the percentage of noisy apartments was 10%, that probability would be 0.9^6 = 0.53. So, given my experience, the latter case is 0.53 / 0.000001 = 530,000 times more probable. |
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