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by wruza
760 days ago
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Because to negate you invert (so & = 0) and add one, which overflows former zeroes until it meets a former one, which flips, so & gives 1 there. Former zeroes are how even a number is. 01100 (12, 2 bit even)
10011 (inv 12, & = 0)
10100 (inv 12 +1 aka -12)
00100 &, 2 bit even
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