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by msandford
758 days ago
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I don't follow how stacking two terminals cuts the clamping force in half. If a screw provides 10lbs of clamp force, the equal and opposite reaction is that the thing it is screwed into must resist with 10lbs. If you put one terminal in between it must transmit all 10lbs through itself or else the forces don't balance out and something must be accelerating. If you then stack another one in there all the force must be transmitted through it also. So the screw clamps with 10lbs of force and both terminals feel 10lbs of clamp force. I just can't figure out where you got the idea of "it cuts the clamp force in half" but I'm interested to hear. |
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It's easy to visualize if you replace the two rings with one enormous ring (and fastener, etc.) while F remains the same: obviously the distributed force at any point will be low.
The distributed force is crucial. Friction in real mechanical systems is non-linear. Conductors made of real materials vary in yield strength. A correctly engineered terminal must account for force, yield strength, area, vibration, dissimilar metals and other factors to prevent back off, gas ingress (thus corrosion,) high resistance etc. Real engineers don't do all the materials science involved here and no one would trust it if they tried: they rely on published standards, authored in blood.
Stacking ring terminals torpedoes all that: what was (relatively) simple with one ring becomes unanalyzed and prone to failure when stacked.