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by eieio
5129 days ago
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I felt the same about number 3. [x in tweet.split() for x in wordlist]
Seems better to me than map(lambda x: x in tweet.split(),wordlist)
Although the natural thing for me to do would be [x for x in wordlist if x in tweet]
Which both generates a list of words instead of booleans(['scala', 'sbt'] instead of [True, False, False, False, False]) and also matches the 'sbt' in tweet. |
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