[jstimpfle]

first, yes it did accept the pointer arithmetic even though it issued a warning.

Second, the error about implicit conversion from void-pointer to typed-pointer is in C++ only -- not in C, where you won't even get a warning. The error happens because you didn't cast the void pointer to the target type and doesn't have to do anything with the fact that gcc _does_ let you (as a GCC extension) do arithmetic on void pointers.

If you remove the "+ 1" you'll still see the same error in C++. In C++, change the target pointer to a void pointer:

   void *ptr = malloc(42) + 1;

or, alternatively, cast the RHS expression properly (doesn't matter with "+ 1" or without)

   int *ptr = (int *) (malloc(42) + 1);

and the error will go away.

[menaerus]

I don't think there's a need to explain to me how pointers work, or what to do to make this error/warning go away, since it should be pretty obvious from my response that this is something I know very well.

I was only disputing the claim that ending up with the unaligned ptr is not trivial for given line of code by providing explanation, and counter-example, why this is not possible. At least not in C++ because that's the language I had in mind.

What you're saying is that it's possible to do void pointer arithmetic in C by using the GNU extension - fine, I can't disagree with that.

[jstimpfle]

You corrected me and I corrected you. No need to take personal offense. I don't care what you know -- I obviously took the compiler output that you presented above as a refutal to what I said earlier, and I pointed out why it's not a valid refutal.