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by eru
797 days ago
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> We don't know that factorization is NP-complete. Yes? No one ever said it was. None of the common cryptographic problems are expected to be NP-complete, even if they aren't in P. That's because they are known to be in both NP and in co-NP, and it's expected that NP != co-NP. > I think a better definition of NP is "only nonpoly algos can exist, no P algos can exist". In what sense is that a 'better' definition than the standard definition? It sounds like what you are talking about is NP\P (where \ is set subtraction, ie 'NP minus P'). |
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I don't even know what co-NP is. Could you explain?
I think that's a better definition because I find it more predictive and useful to think about: pretty concrete to know that you can't have a polytime algo for it.
Yeah, I guess what you're saying about NP\P is right in that it's a restatement of the definition of what I said, haha! I'm not an expert this is just what I think :)