This doesn't make 13 a power of two. I'm aware of rejection sampling; my point was if you have a N bit value X and want M bits, truncating X to M bits and X MOD 2*M is the same. Neither solve the problem where M > N, which is what TFA is about.
I don't see the number 13 in any of my comments on this thread (except this one, or where I quoted you). Perhaps you are confusing me with someone else?
This doesn't make 13 a power of two. I'm aware of rejection sampling; my point was if you have a N bit value X and want M bits, truncating X to M bits and X MOD 2*M is the same. Neither solve the problem where M > N, which is what TFA is about.