|
|
|
|
|
by magicalhippo
815 days ago
|
|
> If the detector at Bob's site influences what Charlie would see at an aggregate level Charlie doesn't see anything. He sends the electrons here and there. He's just produced the entangled electrons, he hasn't measured them. If he did he would destroy the entanglement and ruin the experiment (which is what secure quantum communication is about). Unless he gets some reply (say a photon or electron sent by Bob), he doesn't know what either measure. But if he does get a return particle then they're just communicating classically, so why not just pick up a phone? |
|
Stated differently, the framing I saw was that the "spooky" action was somehow setting detector C to a specific setting would cause a different reading in detector B. And this was done in such a way that B could not know that C had changed. But, simply getting a new reading at B means that either A or C has changed, necessarily?
And again, going off old memory. Never my area of study, such that I assume I am misunderstanding. It is frustrating because most "pointing out my mistake" assumes I care about individual protons. I'm saying if we can agree to have A set to send with constant rate, then barring that getting broken, it seems you have a scheme whereby B and C can know what they are doing in aggregate.