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by bgnn
824 days ago
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a lot of good answers. just couple points to add:
- Charging a capacitor from 0 to Vdd volts takes E=CVdd^2 amount of energy. To find the power (energy/second) you need to multiply this with how frequently you do this, i.e. clock frequency. So, P=FCVdd^2. So most digitak circuits power scales linearly with frequency, and quadratically with power supply voltage Vdd. - Half of themis power is resistive loses. This is kinda a fundamental thing. Charging a capacitor with a resistor is "lossy". - Some of the charge is reused within the circuits |
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