Hacker News new | ask | show | jobs
by fjkdlsjflkds 841 days ago
...but then the algorithmic complexity goes from O(N) to O(N^2), or at least O(N log N), since points have to interact with each other.

(N denotes the number of points you need to generate)

1 comments

I confess I've never used this in a situation where time complexity was at all relevant. For one thing, it is possible that a result only needs to be computed once for each N (and per shape, since this approach works on a wider range of shapes than just spheres).