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by vlovich123
843 days ago
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No - that they are both &mut _ indicates that a mutable reference is being acquired regardless of whether or not they’re used for any mutation. Possibly the compiler could automatically lower to a shared reference if it detects no mutation access locally but there may be design reasons why that’s impossible (+ you can’t have a mutable and a shared reference simultaneously anyway so downgrading to shared would still be disallowed) |
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