[projct]

You are making part of your page always load at least 2 seconds slower than is probably necessary.

$(function(){}); is shortcut for $(document).ready(); which waits until all other external content has been loaded. [1]

If for some reason you are loading something else you need after .ready() fires, and you can't load that inside of a single .ready() call for some reason, you can potentially add multiple callbacks to .ready() (they will be executed in order [2]), or attach a .load() to that particular item instead (maybe even inside your .ready().)

Timeout hacks are not a performance improvement.

[1] http://api.jquery.com/ready/ [2] http://stackoverflow.com/questions/5263385/jquery-multiple-d...

[bentlegen]

$(document).ready does "not wait until all other external content has been loaded". It fires when the DOM is fully parsed, irrespective of whether there are still images or iframes or other assets still loading.

http://stackoverflow.com/questions/4395780/difference-bw-onl...

[j_s]

I think he was getting at the idea that in general each page has some specific-to-the-page JavaScript work to do as soon as it's ready. The delay punts initialization of the less-important plugins, allowing time for the important stuff in a page-generic way. Your point that the delay is a messy way of accomplishing this is certainly valid.