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by rrobukef
904 days ago
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Because you may have meant --f=oo or -f -o -o, both of which are standard unix interpretations of single-dash multi-character flags (e.g. ls, ssh). Or maybe the newest version added the -foo flag. And if you've got something like 'sed' overwriting the input file (-i), it'd better make sure the flags are exactly as documented. |
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