[Peaker]

Here's some Haskell code I really like, and I think it would be far less nice in Python:

  replicateM 10 . forkIO . forever $ do
    ..

Which is basically the same as:

  replicateM 10 (forkIO (forever (do ..)))

replicateM 10 executes its code block argument 10 times. forkIO executes its code block argument in a new thread. forever loops forever.

So this line basically creates a thread pool with 10 threads, all infinitely executing the given code block.

How would you solve this in Python?

[Goladus]

> How would you solve this in Python?

The question is how does codeblocks solve this problem in Python, not how does Haskell solve this problem in Haskell.

[Peaker]

Hypothetical Python:

  times(10, forkIO(forever(block:
     ...
     )))

[Goladus]

That's not what codeblocks does, though. You use a with statement and a new operator (<<). Then use indentation for the blocks. It doesn't look like you're passing a block to a function. The result is quirky code that will be hard to trace and sort out if you don't already know what's happening.

[Peaker]

Oh, I thought you meant code blocks in general, not the particular OP "codeblocks"... Sorry.

I'm not sure that codeblocks actually solves the problem.