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by anon291
948 days ago
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> Irrational numbers can be defined but not 'realized' (or 'constructed') in the same way that the rationals can. Once again, I'm not 100% sure what you're saying. If you have something that's of length 1, then you can easily construct the line with a ratio sqrt(2):1. Draw another line of length 1 (use compass and straightedge) at a 90 degree angle. Repeat 4 times until you have a square. Now draw the diagonal. You have successfully constructed the square root of 2 in your own setup. There are numbers that cannot be constructed geometrically using only a compass and straightedge (e for example). However, again these are no less 'real'. Drawing lines is not the only measure of real. There are other methods. In computing, we often say a number is computable if you can define a function that, given any rational number can tell you if the number it represents is greater than or equal to the rational number. The square root of two and e and pi, etc are easily representable this way. There are some numbers that are not, and perhaps these can truly be said to not exist. However, the field of computables is closed anyway, so it really doesn't matter if you don't want to believe the reals exist. |
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> There are some numbers that are not, and perhaps these can truly be said to not exist.
So then we have a real issue because the vast majority of the real line is composed of these uncomputable numbers which you've suggested don't exist.