[Goz3rr]

USB defaults to 5V, so depending on how much current you want to draw you might not even need a trigger module.

[p1mrx]

USB-C defaults to "off", so a 5V PD trigger would be a sensible product. It just needs a couple resistors, no chip.

[Kirby64]

There’s no such thing as 5V PD unless you mean 5V 5A, fyi. PD is an optionally supported standard of USB-C and the resistors are not part of PD, just the standard USB-C spec.

[p1mrx]

You are technically correct, in that using resistors to trigger 5V would fall under "USB Type-C Current" rather than "USB Power Delivery".

But what would you call such a product, other than "5V PD trigger"?

[joshspankit]

5V USB-C board

[stavros]

You're right, I guess I might as well just get some straight breakouts for a USB-C for the 5V case, but then I'll be limited to half an amp, which is probably fine for my uses, I guess.

[lxgr]

USB-C supports up to 3A without PD, using only (I believe) resistors/voltages to communicate the limit.

That's what many simple early USB-C chargers used to do in order to supply 15W without full PD signalling.

[stavros]

I didn't realize that, thanks!