[saghm]

The part that surprised me is that this would be the way things worked on a modern C++ compiler without any special flags. The article is about C++, and using "magic" memory addresses doesn't seem at all what I'd expect to be the default way to handle division by zero.

From the numerous responses here, it's clear that people interpret my question as about how the hardware itself works, which isn't at all what I was asking about; I'm aware of how stuff like this works at the assembly level, but my understanding was that in C and C++, trying to write arbitrarily to "special" addresses like that would be considered undefined behavior (often resulting in segfaults). When I read the comment I responded to above, it surprised me, so I wanted to check whether I understood what was said correctly. It's honestly kind of confusing to me that so many people seem very upset by the idea that a stranger on the internet might have a misconception about how hardware abstractions are exposed via compiled code to the point that they feel the need to explain in detail how hardware works but not actually answer the question I asked.

[mkup]

The difference between modern days and days of DOS isn't in C/C++ compiler, it's in virtual memory and address space isolation and privilege isolation. So it's not a job of a C/C++ compiler to enforce protection from writing to "special" addresses, because interrupt table updates (and memory-mapped hardware I/O in general) still must happen somewhere (i.e. in kernel, hypervisor, drivers etc) and that code is still written in C/C++, same as in the DOS era.

[sargstuff]

Mmmm..;. job of modern OS is to use/manage MMU. Prior to DEC, OS just automated version of human feeding punch cards/spooling up tape.

DEC provided the necessary hardware MMU to do actual real time multi-processing/multi-user access in feasibile/practical manner.

[lmm]

> The article is about C++, and using "magic" memory addresses doesn't seem at all what I'd expect to be the default way to handle division by zero.

They're not saying this is, like, a portable standard way to handle division by zero in C++. You're right that it would be undefined behaviour under the standard (but a C++ compiler for real-mode x86 would be expected to support it, at least implicitly; obviously this specific case is not a particularly useful, but C++ is used in embedded settings and setting a custom interrupt handler is something its users want and expect).

A decent, well-behaved language would do some kind of structured error handling on divide by zero, like throwing an exception. IMO that includes any C++ compiler worth bothering with (though again the standard makes it undefined behaviour so it's possible that some compilers don't). But, the way the runtime of such a decent C++ compiler would actually implement that would be by setting up an interrupt handler for the divide by zero interrupt (that would contain code to construct the exception etc.), and by performing this write to address 0 you're overwriting (the pointer to) that interrupt handler. So, this line of code would cause your program to behave (almost certainly) badly on the next division by zero, even if you were using a well-behaved C++ compiler that normally handled division by zero gracefully.

(OTOH with a maliciously pedantic C++ compiler that division by zero would already be undefined behaviour, so in practice, since most C++ compilers tend to be maliciously pedantic, you might be no worse off than you were before that line).

The original post you replied to was just talking about the somewhat interesting details of what would actually happen because of the quirks of what these addresses are used for on that hardware (e.g. the fact that address 0 is supposed to contain a pointer to the handler, so by setting it to 0 you cause the CPU to start executing the interrupt handler table as code, is kind of interesting - not as a point about C++, but as a point about funny emergent behaviour of hardware), not about what this is specified as doing or the normal way of doing things in C++. I don't know why you were downvoted.

[sargstuff]

> ".. the fact that address 0 is supposed to contain a pointer to the handler .."

What got missed though, is ther has to be an "unused"/"reserve" bit(s) space in order for things to run without requiring additional specific hardware operations.