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by GolDDranks 977 days ago
You "clearly" is not so clear.

BB(754) is an uncomputable number. It's independent of ZFC, so an enumeration of all consequences of axioms of ZFC doesn't contain it. How is that supposed TM of yours is supposed to know whether it has run BB(754) steps or not?

Oh, but other slightly bigger TMs exist – lets say in class TM(860) for the sake of an example – that might halt with after a more steps than BB(754). This _sounds_ intuitive. But: how do you prove that? It might be that all TM(860)s either halt within BB(754) steps or then run forever. There indeed might be some that halt in finite steps after BB(754), but that is not guaranteed! You need to prove it. But with what?

1 comments

Oops, never mind, there exists a simple construction that you can perform to each TM(754) that clearly extends BB(754) a finite amount. Maybe you are corrent that such Turing machine exists. But seems that identifying it isn't possible in ZCF.
I agree that the problem is identifying the machine, not its existence.