if Earth sqm = 2^49:
to address a single metre, we'd need 49 bits.
log_10(2^49) = 14.75 so we'd need 15 spoken decimal digits for 1 sqm. for 8m do log_10(2^47)
> if Earth sqm = 2^49: to address a single metre, we'd need 49 bits.
Yes-- that's why I said it was 46 bits for an 8 square meter area (because this is about the size of area you care about for this problem-- W3W is 9 square meters).
> for 8m do log_10(2^47)
No, because 2^3 = 8, so one does log_10(2^(49-3)) and gets 13.8. 46 / 3.3 =~ 13.9 works because 1/log_10(2) =~ 3.3.
Yes-- that's why I said it was 46 bits for an 8 square meter area (because this is about the size of area you care about for this problem-- W3W is 9 square meters).
> for 8m do log_10(2^47)
No, because 2^3 = 8, so one does log_10(2^(49-3)) and gets 13.8. 46 / 3.3 =~ 13.9 works because 1/log_10(2) =~ 3.3.