[dataflow]

Confused, why do you think this is a compiler bug? You should definitely expect a predictable branch to be faster than a conditional move, and the insertion of a conditional move in the original is totally sensible (albeit not intuitive if you haven't seen it).

[littlestymaar]

> and the insertion of a conditional move in the original is totally sensible (albeit not intuitive if you haven't seen it).

Would you mind expanding? If the conditional move isn't needed, and given that it's costly in terms of perfs, how is that “totally sensible” to have one here?

[dataflow]

The performance of branches is data-dependent. The performance of conditional moves is data-independent. In this case the branches are predictable, so they perform better here. In general, though, the compiler has no idea whether that's the case, so it makes sense to insert a conditional move to avoid branch misprediction penalties.

[mcv]

But still, why the difference? With or without the "lol", the data dependence is identical, the predictability is identical. Yet with the "lol" it optimises differently.

My best guess is that it's because of the added cost to the other branch: printing is expensive, so the compiler really doesn't want to do that, and would prefer to incorrectly predict not-printing than to incorrectly predict printing.

If that tradeoff is what causes the difference in behaviour here, then I understand. But I don't like it, because it's ridiculous and we shouldn't have to con the compiler into doing what's right. If we're going to have to do this, I'd rather have the language provide a way for us to make explicit what we expect here.

[anonymoushn]

When compiling code like

  if a > b
    b = a
    continue
  else
    continue

you can replace the entire if-else with a cmov. but if there is a function call in one of the prongs and not in the other, you cannot.

[mcv]

Ah, so it's the function call (which could just as easily have been something other than print), that forces the compiler to use a normally-less-optimal branch rather than the normally-more-optimal cmov. Only in this particular use case, cmov is actually less optimal, but the compiler doesn't know that.

[fmstephe]

This is a very good answer. Thanks.

[tylerhou]

https://news.ycombinator.com/item?id=36623759

[littlestymaar]

Thank you.