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by anonymoushn 1035 days ago
Your link seems to say it has time complexity O(n)?
1 comments

If you count everything carefully, it's O(n / log log n)

https://www.ams.org/journals/mcom/2004-73-246/S0025-5718-03-...

They are essentially the same in all conceivable practical cases in this Universe.

log log (atoms in universe) < 100

This seems to be a matter of the above source reporting a variation of the algorithm that is asymptotically slower than the algorithm given in the paper *and* uses asymptotically more memory. Thanks for posting the paper!