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by fooker
1032 days ago
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It's not by definition, there's a bit of math behind it! :) The intuition is that the hardest problems in P have linear dependency chains.
If you could have a good parallel algorithm for a P complete problem, you could take a problem with a dependency chain and solve parts of it in parallel without waiting for the results those parts are depending on. |
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Is there a formal proof of what you're talking about that we can read?