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ithkuil
1048 days ago
I'm confused. Since O(log n) is faster than O(n) why would O(n) require a little more work? Did I misread something or did you miswrite?
1 comments
pfdietz
1048 days ago
I'm talking about constructing boolean circuits. The usual parallel prefix algorithm yields a circuit of depth O(log n) with O(n log n) gates. Using some trickery, however, this can be reduced to O(n) gates, with a constant factor increase in depth.
https://en.wikipedia.org/wiki/Prefix_sum
https://en.wikipedia.org/wiki/Adder_(electronics)
link
ithkuil
1048 days ago
Constant depth requires unbounded fan-in, which may not be available in practice
link
pfdietz
1040 days ago
Yes, I was talking about using gates of bounded fan-in.
link
https://en.wikipedia.org/wiki/Prefix_sum https://en.wikipedia.org/wiki/Adder_(electronics)