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ez667
1061 days ago
12.0200112_e = e+2+2/e^2+e^-5+e^-6+2e^-7 = 4.99999285804.....
so 5 in base e is an infinite sequence of digits starting with 12.020011....
1 comments
joe__f
1060 days ago
How many digits do you need to do this for a given transcendental?
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