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by placesalt
1100 days ago
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The answer by user 'Blue' on the same thread seems more practical to me. Their answer[1] uses notation that doesn't translate to this messageboard. Perhaps a reordering of their method, using the existing caret notation: b^p = r :: the result from base b with exponent p
^pr = b :: the base giving result r from exponent p
br^ = p :: the exponent yielding r with base b
[1] https://math.stackexchange.com/a/1158802 |
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