|
|
|
|
|
|
by bombela
1098 days ago
|
|
|
Wikipedia also says that water starts conducting at 1.23V, and the common Li-Ion nominal voltage is 3.7V. 3.7V - 1.23V == 2.47V.
2.47V / 0.2Ω ~= 30W (12.5A). You will be able the find your phone on the seabed from the bubble emanating from it. Though the battery protect circuitry (which is inside the battery package) will most likely cut power before the battery is risks damages. |
|
|
I wonder if that's responsible for the experiences folks had way before waterproof phones were introduced: they would drop their phone into water, it would shut off and refuse to boot for a significant amount of time (enough to send them shopping for a replacement) and then they'd try it a week later only to find that it works fine. Accelerated by putting it in a bag with rice or other desiccant.