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by pjmlp
1116 days ago
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True, but it also adds lot of features that help to easily migrate to saner features without rewriting the world and throw away 30 years of tooling. Microsoft security team is on the record that just because they are adopting Rust, they won't shy away from C++. |
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Example, Rust 1.0 had std::mem::uninitialized::<T>() which gives a T but it's obviously uninitialized. It's marked "unsafe" of course, but is that enough? Turns out they later realised that no, it's strictly never OK to do this, so the unsafe label was insufficiently cautious. Today std::mem::uninitialized is deprecated, Rust never removes stuff from the standard library, but you should not use this library call.
The type MaybeUninit<T> is the fix. Since MaybeUninit<T> might not be initialized, it's OK if it's not initialized, and since it might be T, it's OK for it to occupy the same amount of space as T. So, then we can initialize this memory, and tell the compiler it's initialized now, it's a T not a MaybeUninit<T>.
Can you guess how that works? It's pretty clever, and C++ could do almost the same trick, but it never has and my guess is it never will. If you don't know and are wondering, check that type definition carefully - MaybeUninit<T> is a union
For contrast, in his safety talk Bjarne Stroustrup just says as if it's obviously true, that it's safe to have uninitialized char arrays in C++. And his rationale sounds exactly like how std::mem::uninitialized happened - any possible value of a byte is a valid byte, so that's good enough, right? Nope, ask compiler engineers, there were plenty in the room when Bjarne said that, but he didn't ask them.