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by lmm 1111 days ago
Because replica failover is rarely seamless (and often doesn't actually work at all, IME).
1 comments

Instinctively that's surprising... replica failover should be far simpler technically, shouldn't it?
No? Replication tends to be a bodged-on mess throughout, full of undertested edge cases, of which failover is definitely one. If you build the system so that nodes joining and leaving is a natural and normal part of operation, well, it naturally works a lot better.