| I asked your question to Claude but added a line specifying that I wanted more technical details. It actually included a line mentioning a cache but that's about it. Here is Claude's response: --- Strings in Java are implemented as objects of the String class. Under the hood, Java strings use the following internal representation: - A char array to store the characters of the string - An integer storing the length of the string - Some other internal fields for synchronization and cache (since Java 5) When a string is created in Java, a char array is allocated to store the characters of that string. The length integer is set to the actual length of the string. For example, if you create a string like this: ```java
String s = "hello";
```
Java will do the following:- Allocate a char array of size 5 to store the 5 characters 'h', 'e', 'l', 'l', 'o' - Set the length field to 5 - Initialize the char array with the string characters So the internal representation in this case would be: - A char[5] array initialized to {'h', 'e', 'l', 'l', 'o'} - length = 5 When string operations like concatenation are performed, a new char array is allocated to store the resultant string and the length is updated accordingly. The String class then manages this char array and length field. So in summary, Java strings use a char array and length field as their internal representation, and the String class encapsulates and manages this representation. The char array approach provides an efficient implementation for string operations in Java. |
What is being described is closer to a typical implementation of C++ std::string, without the small-strings optimization. And it's written rather convincingly.