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by rtpg
1141 days ago
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What series of operations can lead you to end up with dy/dx though? Like Integral{x^2){dx} is how you're introducing dx into a formula, but it's not like integration just works over division, so I'm a bit stuck on the construction phase |
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dy = 2x dx
dy/dx = 2x
Chain rule makes this not completely trivial formulation.